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mosquito · 10-08-2000, 10:08 AM

use the msxml object. It's the same way you would do it with vb.

Code:

Set oXml = createobject("msxml.XMLDocument")
oXml.URL = FilePath
Set xRoot = oXml.root

This way the complete structure of the xml file is exposed.

10-08-2000, 10:08 AM	#2
mosquito SQL nutcase Join Date: Sep 2000 Location: Belgium Posts: 1,136	use the msxml object. It's the same way you would do it with vb. Code: Set oXml = createobject("msxml.XMLDocument") oXml.URL = FilePath Set xRoot = oXml.root This way the complete structure of the xml file is exposed. __________________ Join The PCMech RC5 Team Today!