Cal problem

[boxcarracer767]

I have a question on finding the g(f(x)=H
f(x)=lsinxl, -pi<= x <= pi, and g(x)=x2

To find H(x)= (lsinxl)^2
Is this right and it equal to sin^2x
and How would I find the domain an range of h(x)
and tangent line to the graph h at x=pi/4

Would I have to take the deriviative of H to find the tangent line??

Thanks for the help, my teacher didn't explain any of this to our class.

[doctorgonzo]

Yes, that's right. You will have to take the derivative of H(x) to find the tangent. Have you learned the chain rule yet? This is an applicable case.