Passing a 2 dimensional array through a function

[faint545]

Quick question here.

How do you pass a two-dimensional array containing characters through a function?
I keep getting this

error 26 C:\Dev-Cpp\Projects\project8.cpp cannot convert `char (*)[10]' to `char*' for argument ` 1' to `void phase2(char*, int)'

this is what i have..

void phase2(char [], int); int main() { const int rows = 12, colums = 10; char months[rows][colums] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"}; phase2(months, rows); return 0; } void phase2(char all_months[], int month_postition) { cout << "I'm in phase 2"; }

[kram 2.0]

Perhaps you will need to change the argument-type for the function from a one-dimensional array to a two-dimensional array? Instead of:

PHP Code:

void phase2(char all_month[], int month_position) 


Try:

PHP Code:

void phase2(char all_month[][cols]) 


Be sure to change the appropriate prototype for the function as well to reflect the changes you've made within the function.

kram

[Force Flow]

I'm not familar with C++, and may be making a few assumptions about the language, but shouldn't you be using string instead of char?

[Rapier]

Originally Posted by faint545 Quick question here. How do you pass a two-dimensional array containing characters through a function? I keep getting this this is what i have..

Wow! I'll bet that hurt.